class Solution:
def atMostNGivenDigitSet(self, D: List[str], N: int) -> int:
S = str(N)
K = len(S)
dp = [0] * K + [1]
for i in range(K-1, -1, -1):
# Compute dp[i]
for d in D:
if d < S[i]:
dp[i] += len(D) ** (K-i-1)
elif d == S[i]:
dp[i] += dp[i+1]
return dp[0] + sum(len(D) ** i for i in range(1, K))
22A - Second Order Statistics | 1720B - Interesting Sum |
1720A - Burenka Plays with Fractions | 3A - Shortest path of the king |
1720C - Corners | 574A - Bear and Elections |
352B - Jeff and Periods | 1244A - Pens and Pencils |
1670A - Prof Slim | 1189A - Keanu Reeves |
678A - Johny Likes Numbers | 1699C - The Third Problem |
1697D - Guess The String | 754B - Ilya and tic-tac-toe game |
760A - Petr and a calendar | 1573A - Countdown |
166A - Rank List | 1631B - Fun with Even Subarrays |
727A - Transformation from A to B | 822B - Crossword solving |
1623A - Robot Cleaner | 884B - Japanese Crosswords Strike Back |
862B - Mahmoud and Ehab and the bipartiteness | 429A - Xor-tree |
1675C - Detective Task | 950A - Left-handers Right-handers and Ambidexters |
672B - Different is Good | 1C - Ancient Berland Circus |
721A - One-dimensional Japanese Crossword | 1715B - Beautiful Array |